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Number Matrix(संख्यात्मक म्याट्रिक्स)

Number Matrix(संख्यात्मक म्याट्रिक्स)-

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Matrix मा last row मा last column हेर्नुपर्छ जसका आधारमा जोड, घटाउ, गुणन, भाग गरी समाधान गर्न सकिन्छ ।

Example 1 :


यहाँ, पहिलो column मा (R2×R3R1)=4×71=27 दोश्रोcolumn मा त्यसैगरी 5×82=38तेस्रोcolumn मा त्यसैगरी 6×93=51यहाँ, छुटेको नम्बर 51 हुन्छ।\text{यहाँ, पहिलो column मा }\left(\mathrm{R}_2 \times \mathrm{R}_3-\mathrm{R}_1\right)=4 \times 7-1=27\\ \text{ दोश्रोcolumn मा त्यसैगरी }5 \times 8-2=38 \\\text{तेस्रोcolumn मा त्यसैगरी } 6 \times 9-3=51 \\ \text{यहाँ, छुटेको नम्बर 51 हुन्छ।}

Example 2 :

20301234880?116\begin{array}{|l|l|l|} \hline 20 & 30 & 12 \\ \hline 3 & 4 & 8 \\ \hline 80 & ? & 116 \\ \hline \end{array}

यहाँ, गुणन, जोड, घटाउबाट उत्तर आउँदैन, त्यसैले

20×3+20=8030×4+20=14012×8+20=116\begin{aligned} & 20 \times 3+20=80 \\ & 30 \times 4+20=140 \\ & 12 \times 8+20=116 \end{aligned}

Example 3 :

6152084535205165?6×8+3=5115×4+5=6520×5+20=120\begin{aligned} &\begin{array}{|c|c|c|} \hline 6 & 15 & 20 \\ \hline 8 & 4 & 5 \\ \hline 3 & 5 & 20 \\ \hline 51 & 65 & ? \\ \hline \end{array}\\ &\begin{aligned} & 6 \times 8+3=51 \\ & 15 \times 4+5=65 \\ & 20 \times 5+20=120 \end{aligned} \end{aligned}

Example 4 :

FIOAJKEM?a)Pb)Rc)Sd)V\begin{array}{|c|c|c|} \hline \mathrm{F} & \mathrm{I} & \mathrm{O} \\ \hline \mathrm{A} & \mathrm{J} & \mathrm{K} \\ \hline \mathrm{E} & \mathrm{M} & ? \\ \hline \end{array}\\ a) P\\ b) \mathrm{R}\\ c) \mathrm{S}\\ d) \mathrm{V}\\

यहाँ, coding - decoding अनुसार

F=6I=90=15A=1 J=10 K=11E=5 m=13R=18\begin{array}{|l|l|l|} \hline \mathrm{F}=6 & \mathrm{I}=9 & 0=15 \\ \hline \mathrm{A}=1 & \mathrm{~J}=10 & \mathrm{~K}=11 \\ \hline \mathrm{E}=5 & \mathrm{~m}=13 & \mathrm{R}=18 \\ \hline \end{array}

Example 5 :

5161116432303543?\begin{array}{|c|c|c|} \hline 51 & 61 & 11 \\ \hline 64 & 32 & 30 \\ \hline 35 & 43 & ? \\ \hline \end{array}

a)25b)27c)32d)37a) 25\\ b) \mathrm{27}\\ c) \mathrm{32}\\ d) \mathrm{37}\\

यहाँ,C1C2लाई प्रयोग गरेर C3बनाईएको छ, त्यसैले5×1+6×1=116×4+3×2=303×5+4×3=27यहाँ, \mathrm{C}_1 \mathrm{C}_2 \text{लाई प्रयोग गरेर }\mathrm{C}_3 \text{बनाईएको छ, त्यसैले}\\ \begin{aligned} & 5 \times 1+6 \times 1=11 \\ & 6 \times 4+3 \times 2=30 \\ & 3 \times 5+4 \times 3=27 \end{aligned}

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Laxman Nepal is a multi-talented individual with expertise in computer teaching, blogging, video editing, and more. With years of experience in his field, Laxman has established himself as a reliable…

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